类别:PHP问题 / 日期:2019-12-02 / 浏览:96 / 评论:0

经由过程php模仿post要求即可挪用。
引荐:php服务器
php模仿POST提交的2种要领
1、经由过程curl函数
PHP中运用cURL完成Get和Post要求的要领
$post_data = array(); $post_data['clientname'] = "test08"; $post_data['clientpasswd'] = "test08"; $post_data['submit'] = "submit"; $url='http://xxx.xxx.xxx.xx/xx/xxx/top.php'; $o=""; foreach ($post_data as $k=>$v) { $o.= "$k=".urlencode($v)."&"; } $post_data=substr($o,0,-1); $ch = curl_init(); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_URL,$url); //为了支撑cookie curl_setopt($ch, CURLOPT_COOKIEJAR, 'cookie.txt'); curl_setopt($ch, CURLOPT_POSTFIELDS, $post_data); $result = curl_exec($ch);
2、经由过程fsockopen.
fsockopen — 翻开一个网络衔接或许一个Unix套接字衔接
$URL=‘http://xxx.xxx.xxx.xx/xx/xxx/top.php'; $post_data['clientname'] = "test08"; $post_data['clientpasswd'] = "test08"; $post_data['submit'] = "ログイン"; $referrer=""; // parsing the given URL $URL_Info=parse_url($URL); // Building referrer if($referrer=="") // if not given use this script as referrer $referrer=$_SERVER["SCRIPT_URI"]; // making string from $data foreach($post_data as $key=>$value) $values[]="$key=".urlencode($value); $data_string=implode("&",$values); // Find out which port is needed - if not given use standard (=80) if(!isset($URL_Info["port"])) $URL_Info["port"]=80; // building POST-request: $request.="POST ".$URL_Info["path"]." HTTP/1.1\n"; $request.="Host: ".$URL_Info["host"]."\n"; $request.="Referer: $referrer\n"; $request.="Content-type: application/x-www-form-urlencoded\n"; $request.="Content-length: ".strlen($data_string)."\n"; $request.="Connection: close\n"; $request.="\n"; $request.=$data_string."\n"; $fp = fsockopen($URL_Info["host"],$URL_Info["port"]); fputs($fp, $request); while(!feof($fp)) { $result .= fgets($fp, 128); } fclose($fp);
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